) Professor Jin wants to travel from place A to place B without a map. There are four ways lead away from place A. If road I is selected, the probability of arriving place B is 1/8; if road II is selected, the probability of arriving place B is 1/6; if road III is selected, the probability of arriving place B is 1/4; and if road IV is selected,the probability of arriving place B is 9/10. (a) What is the probability that professor will arrive at place B

Respuesta :

Complete Question

Professor Jin wants to travel from place A to place B without a map. There are four ways lead away from place A. If road I is selected, the probability of arriving place B is 1/8; if road II is selected, the probability of arriving place B is 1/6; if road III is selected, the probability of arriving place B is 1/4; and if road IV is selected,the probability of arriving place B is 9/10.

(a) What is the probability that professor will arrive at place B?

(b) If Professor Jin arrives at place B, what is the probability that she chooses road IV?

Answer:

a

  [tex]P(B) = 0.36[/tex]

b

  [tex]P(4 /B) = 0.62[/tex]

Step-by-step explanation:

From the question we are told that

  The number of ways from A to B is  n =  4

   The  probability if road 1 is selected is  [tex]P(1) = \frac{1}{8}[/tex]

   The  probability if road 2 is selected is  [tex]P(2) = \frac{1}{6}[/tex]

    The  probability if road 3 is selected is [tex]P(3) = \frac{1}{4}[/tex]

    he  probability if road 4 is selected is [tex]P(4) = \frac{9}{10}[/tex]

The probability that professor will arrive at place B is mathematically represented as

      [tex]P(B) = \frac{1}{n} * P(1) + \frac{1}{n} * P(2) + \frac{1}{n} * P(3)+ \frac{1}{n} * P(4)[/tex]

      [tex]P(B) = \frac{1}{4} * \frac{1}{8} + \frac{1}{4} * \frac{1}{6} + \frac{1}{4} * \frac{1}{4} + \frac{1}{4} * \frac{9}{10}[/tex]

      [tex]P(B) = 0.36[/tex]

If Professor Jin arrives at place B, what is the probability that she chooses road IV is mathematically represented as

      [tex]P(4 /B) = \frac{ \frac{1}{n} * P(4)}{P(B)}[/tex]

=>     [tex]P(4 /B) = \frac{ \frac{1}{4} * \frac{9}{10} }{0.36}[/tex]

=>      [tex]P(4 /B) = 0.62[/tex]