Answer:
When a= -8, the equation 3(2x-a) = 2(3x+12) has infinitely many solutions
Step-by-step explanation:
Given:
3(2x-a) = 2(3x+12)
6x - 3a = 6x + 24
Subtract 6x from both sides
6x - 3a - 6x = 6x + 24 - 6x
-3a = 24
Divide both sides by -3
a= 24 / -3
a = -8
Substitute a= -8 into the equation
3(2x-a) = 2(3x+12)
3{2x -(-8)} = 2(3x+12)
3(2x + 8) = 2(3x +12)
6x + 24 = 6x + 24
6x - 6x = 24 - 24
0 = 0
When a= -8, the equation 3(2x-a) = 2(3x+12) has infinitely many solutions
