Answer:
His average rate of speed for the entire trip is 10 miles/hour.
Step-by-step explanation:
We are given that John went on a bike ride to the store 4 miles away. If it took John 3/10 of an hour to get there and 1/2 of an hour to get back.
And we have to find his average rate of speed (miles per hour) for the entire trip.
As we know that the Distance-Speed-Time formula is given by;
[tex]\text{Speed}=\dfrac{\text{Distance}}{\text{Time}}[/tex]
Here, the distance for the entire trip = 8 miles (4 miles for reaching store and 4 miles for returning back)
The time taken for the entire trip = [tex](\frac{3}{10} )[/tex] of an hour to reach the store and [tex](\frac{1}{2})[/tex] an hour to get back.
So, the average rate of speed for the entire trip = [tex]\frac{\text{Total Distance}}{\text{Total Time}}[/tex]
= [tex]\frac{8}{\frac{3}{10}+\frac{1}{2} }[/tex]
= [tex]\frac{8}{\frac{8}{10} }[/tex] = 10 miles per hour
Hence, his average rate of speed for the entire trip is 10 miles/hour.
