Answer:
second order
Explanation:
units of reaction and their order.
Zero order --> M^1 s^-1 = M/s
First order --> M^0 s^-1 = 1/s
Second order --> M^-1 s^-1 = L/mol s
In the question rate constant k = 4.65 L mol-1s-1. = 4.65 L/mol s
Hence, the reaction is a second order reaction
Answer:
The answer is "second".
Explanation:
Given:
rate constant for a reaction = 4.65 [tex]\frac{L}{mol \cdot s}[/tex]
[tex]\text{The rate of unit} = \frac{m}{s} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ _{where} \ \ M=\frac{mol}{l} \\\\[/tex]
[tex]=\frac{mol}{l \cdot s}[/tex]
The orders unit value of the k
0 [tex]\frac{m}{s}[/tex]
1 [tex]\frac{1}{s}[/tex]
2 [tex]\frac{l}{m s}[/tex]
The rate of the unit is constant for the second-order that's why it is correct.
