Answer:
The path difference will be zero.
Explanation:
Given that,
In a young's double-slit experiment the center of a bright fringe occurs wherever waves from the slits differ in the distance.
Suppose, we find the multiple of wavelength
In young's double slit experiment,
We need to calculate the multiple of wavelength
Using formula of path difference
[tex]\Delta x=d\sin\theta[/tex]....(I)
[tex]d\sin\theta=m\lambda[/tex]
Where, m = fringe number
[tex]\lambda[/tex] = wavelength
For center of a bright fringe ,
m = 0
Put the value into the formula
[tex]d\sin\theta=0\times\lambda[/tex]
[tex]d\sin\theta=0[/tex]
Put the value in equation (I)
[tex]\Delta x=0[/tex]
Hence, The path difference will be zero.
