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Water is boiling in a pan at 100 oC. If heat is transferred to the pan at a rate of 2 kW, how much water, in kg, will evaporate in 10 minutes?

Respuesta :

Answer:0.531 kg

Explanation:

Heat absorbed by water in 10 minutes is 10*60*2=1200Kj

As latent heat of evaporation is 2260 kj/kg

Now water evaporation in 10 minutes would be 1200/2260 =0.531 kg

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