Respuesta :
Answer:
1 + sin2x
Step-by-step explanation:
Given
(sinx + cosx)² ← expand using FOIL
= sin²x + 2sinxcosx + cos²x
[ sin²x + cos²x = 1 and sin2x = 2sinxcosx ]
= 1 + sin2x
Answer:
[tex]1 + 2 \times \sin(x ) \times \cos(x) [/tex]
Step-by-step explanation:
[tex]( \sin(x) + \cos(x) \: )^{2} [/tex]
By expanding it , we get
[tex] { \sin }^{2} x \: + { \cos }^{2} x \: + \: 2 \times \sin(x) \times \cos(x) [/tex]
we know that
[tex] { \sin}^{2} x + { \cos }^{2} x = 1[/tex]
so,
[tex] { \sin }^{2} x + { \cos}^{2} x + 2 \times \sin(x) \times \cos(x) = 1 + 2 \times \sin(x) \times \cos(x)[/tex]
