Answer:
Solubility = [SO₄²⁻]
Explanation:
Solubility of Ag₂SO₄ can be determined by its ksp equilibrium:
Ag₂SO₄(s) ⇄ SO₄²⁻ + 2Ag⁺
Where 1 mole of silver sulfate dissolves producing 1 mole of sulfate ion and 2 moles of silver ion.
Solubility is defined as the amount of solid that can be dissolved per liter of solution.
The moles of Ag₂SO₄ dissolved are equal to moles of SO₄²⁻.
That means:
Solubility = [SO₄²⁻]
