contestada

What will be the force if the particle's charge is tripled and the electric field strength is halved? Give your answer in terms of F

Respuesta :

hamzaahmeds

Answer:

F' = (3/2)F

Explanation:

the formula for the electric field strength is given as follows:

E = F/q

where,

E = Electric Field Strength

F = Force due to the electric field

q = magnitude of charge experiencing the force

Therefore,

F = E q   ---------------- equation (1)

Now, if we half the electric field strength and make the magnitude of charge triple its initial value. Then the force will become:

F' = (E/2)(3 q)

F' = (3/2)(E q)

using equation (1)

F' = (3/2)F

onyebuchinnaji

When the charge of the particle is tripled, and magnetic field strength is halved, the force increases by factor of 1.5 (1.5 F)

The force experienced by a particle placed in magnetic field is given as;

F = qvB

where;

  • q is the charge of the particle
  • v is the velocity of the particle
  • B is the magnetic field strength

When the charge of the particle is tripled, q₂ = 3q and magnetic field strength is halved, B₂ = 0.5B.

The magnetic force of the particle is determined as;

[tex]F = qvB\\\\ v = \frac{F}{qB} \\\\ \frac{F_1}{q_1B}_1 = \frac{F_2}{q_2B_2}\\\\ F_2 = \frac{F_1 q_2B_2}{q_1 B_1} \\\\ F_2 = \frac{F \times 3q_1\times 0.5B_1}{q_1B_1} \\\\ F_2 = 1.5 F[/tex]

Thus, when the charge of the particle is tripled, and magnetic field strength is halved, the force increases by factor of 1.5 (1.5 F).

Learn more about magnetic force here: https://brainly.com/question/13277365

Otras preguntas