Answer:
The speed of the car just before braking is 23.66 m/s.
Explanation:
Given;
mark of the skid, d = 80 m
deceleration of the car, a = 3.5 m/s²
To determine the speed of the car just before braking, we apply the following kinematic equation;
[tex]v^2 = u^2 + 2ad\\\\v^2 = 0 + 2(3.5)(80)\\\\v^2 = 560\\\\v= \sqrt{560}\\\\v = 23.66 \ m/s[/tex]
Therefore, the speed of the car just before braking is 23.66 m/s.
