If trapezoid JKLM with vertices) (3, 4), K (6,4), L (8, 1) and M (1,1) is rotated 270 degrees counterclockwise, what are the

coordinates of J'?

Respuesta :

Answer:

[tex]J' = (4,-3)[/tex]

Step-by-step explanation:

Given

[tex]J = (3, 4)[/tex]

[tex]K =(6,4)[/tex]

[tex]L = (8, 1)[/tex]

[tex]M = (1,1)[/tex]

[tex]Rotation = 270CCW[/tex]

Required

Determine the new coordinate of J

From rules of rotation,

When a point (x,y) is rotated 270 degrees CCW;

The new point becomes (y,-x)

Considering point J

[tex]J = (3, 4)[/tex]

This means

[tex](x,y) = (3,4)[/tex]

Where [tex]x = 3[/tex] and [tex]y = 4[/tex]

Using the above rotation rule of

[tex](x,y) -> (y,-x)[/tex]

The coordinates of J' becomes

[tex]J' = (4,-3)[/tex]