Given:-
Initial velocity,u = 26 m/s
Final velocity,v = 18 m/s
Acceleration,a = -2 m/s²
To be calculated:-
Calculate the time take by a body.
Solution:-
According to the first equation of motion:
[tex] \bf \: v = u + at[/tex]
★ Substituting the values in the above formula,we get:
[tex] \sf\implies18 = 26 + ( - 2) \times t[/tex]
[tex] \sf \implies18 = 26 - 2t[/tex]
[tex] \sf \implies \: 2t = 26 - 18[/tex]
[tex] \sf \implies \: 2t = 8[/tex]
[tex] \sf \implies \: t = \cancel\dfrac{8}{2} [/tex]
[tex] \sf \implies \: t = 4 \: sec[/tex]
