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Use the given conditions to write an equation for the line in​ point-slope form and in​ slope-intercept form. Passing through -3, -6) and parallel to the line whose equation is y=-4x+1

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Sueraiuka

Step-by-step explanation:

Hey there!

The equation of a st.line passing through point is;

(y + 6) = m1(x+3).........(i). [ Use one point formula]

y = -4x + 1............(ii)

Comparing 2nd equation with y = mx+c, we get;

Slope (m2) = -4.

For parallel lines;

[tex]m1 = m2[/tex]

(i.e m1=m2 = -4)

Putting value of slope in 1st equation,

[tex](y + 6) = - 4(x + 3)[/tex]

Smplify them to get equation.

[tex](y + 6) = - 4x - 12[/tex]

[tex]y = - 4x - 12 - 6[/tex]

[tex]y = - 4x - 18[/tex]

Therefore the required equation is y = -4x-18.

Hope it helps..

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