Step-by-step explanation:
Hey there!
The equation of a st.line passing through point is;
(y - 8) = m1(x+4).........(i).
And another equation is;
3x - 8y - 7 =0.......(ii)
From equation (ii), we get;
[tex]slope(m2) = \frac{ - coeff. \: of \: x}{coeff. \: of \: y} [/tex]
[tex]m2 = \frac{ - 3}{ - 8} [/tex]
Therefore the slope is 3/8.
As they are parallel lines, their slopes are eaual.
i.e m1 = m2 = 3/8.
Putting value of slope (m1) in equation (i).
[tex](y - 8) = \frac{3}{8} (x + 4)[/tex]
Simplify them to get equation.
[tex]8(y - 8 ) = 3x + 12[/tex]
[tex]8y - 64 = 3x + 12[/tex]
[tex]3x - 8y + 12 + 64 = 0[/tex]
[tex]3x - 8y + 76 = 0[/tex]
Therefore therequired equation is 3x - 8y +76=0.
Hope it helps...
