Please do me a favor and solve this

Answer:
negative 3 an lesser, or positive 4 and greater
Step-by-step explanation:
(0^2=0)-0-12 is not greater than or equal to zero
However, everything equal to or lesser than -3 is equal or greater than zero.
(-3^2=9)-(-3)-12=0
(-4^2=16)-(-4)-12=8
and so on
everything greater than or equal to 4 is greater than or equal to 0 as well
(4^2=16)-4-12=0
(5^2=25)-5-12=8