Answer:
[tex]m=243.72g[/tex]
Explanation:
Hello,
For the given chemical reaction:
[tex]CaO(s) + 3 C(s) \rightarrow CaC_2(s) + CO(g)[/tex]
Whose heat of reaction is 464.8 kJ/mol which means that energy is absorbed due to the chemical reaction, we can compute the moles of calcium carbide via the following relationship:
[tex]n=\frac{1770kJ}{464.8 kJ/mol}\\ \\n=3.81mol[/tex]
Then, since the molar mass of calcium carbide is 64 g/mol, the yielded mass turns out:
[tex]m=3.81mol*\frac{64g}{1mol}\\ \\m=243.72g[/tex]
Best regards.
