To practice Problem-Solving Strategy 2.1 Motion with constant acceleration You are driving down the highway late one night at 20 m/s when a deer steps onto the road 35 m in front of you. Your reaction time before stepping on the brakes is 0.50 s , and the maximum deceleration of your car is 10 m/s2 . How much distance is between you and the deer when you come to a stop?

Respuesta :

Answer:

5 m

Explanation:

First, we need to find the distance traveled by car in the 0.50 s:

[tex] x = v*t = 20 m/s*0.5 s = 10 m [/tex]

Now, we can find the distance traveled by car when the brakes are applied:

[tex] V_{f}^{2} = V_{0}^{2} - 2ax [/tex]

[tex] x = \frac{V_{0}^{2}}{2a} = \frac{(20 m/s)^{2}}{2*10 m/s^{2}} = 20 m [/tex]

Finally, the distance between the car and the deer is:  

[tex] d = 35 m - 10 m - 20 m = 5 m [/tex]

Therefore, the distance between the car and the deer is 5 m.

I hope it helps you!