Suppose that a particle accelerator is used to move two beams of particles in opposite directions. In a particular region, electrons move to the right at 7130 m/sand protons move to the left at 2583 m/s. The particles are evenly spaced with 0.0288 m between electrons and 0.0747 m between protons. Assuming that there are no collisions and that the interactions between the particles are negligible, what is the magnitude of the average current in this region?

Velocity of electrons is 7130 m/s and particles are evenly spaced with 0.0288 m between electrons. We can find no of electrons passing per second as follows :

[tex]n_e=\dfrac{7130\ m/s}{0.0288\ m}\\\\n_e=247569.44[/tex]

Velocity of protons is 2583 m/s and particles are evenly spaced with 0.0747 m between electrons. We can find no of protons passing per second as follows :

[tex]n_p=\dfrac{2583 \ m/s}{0.0747 \ m}\\\\n_p=34578.31[/tex]

Total current in this region is equal to sum of current due to electrons and current due to protons.

[tex]I=n_e\times e+n_p\times e\\\\I=e(n_e+n_p)\\\\I=1.6\times 10^{-19}\times (247569.44+34578.31)\\\\I=4.51\times 10^{-14}\ A[/tex]

Hence, this is the required solution.