Answer:
the answer would be 6
Step-by-step explanation:
the way i got my answer is by adding on to the negative on the 2,-1 then i add 5 to the over all to get 1 plus 5 and get 6.
The distance between the two points (2,-1) and (2,5) is 6 units.
The distance between two points [tex](x_1,y_1),(x_2,y_2)[/tex] is,
[tex]d=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2} }[/tex]
For given example,
Let [tex](x_1,y_1)=(2,-1),(x_2,y_2)=(2,5)[/tex]
Let 'd' be the distance between two points (2,-1) and (2,5).
Using distance formula,
⇒ [tex]d=\sqrt{(2-2)^{2}+(5-(-1))^{2} }[/tex]
⇒ [tex]d=\sqrt{(0)+(5+1)^{2} }[/tex]
⇒ [tex]d=\sqrt{6^{2} }[/tex]
⇒ [tex]d=6[/tex] units.
Therefore, the distance between two points (2,-1) and (2,5) is 6 units.
Learn more about distance between two points here:
brainly.com/question/8792086
#SPJ2
