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Which point-slope equation represents a line that passes through (3,-2) with a slope of -4/5
O y-3 =-4/5(x+2)
Oy - 2 =4/5(x-3)
Oy+2=-4/5(x-3)
O y + 3 = 4/5(x+2)

Respuesta :

Stephen46

Step-by-step explanation:

To find an equation of a line in point slope form when given the slope and a point we use the formula

[tex]y - y_1 = m(x - x_1)[/tex]

where

m is the slope

( x1 , y1) is the point

From the question

the point is (3,-2) and slope - 4/5

The equation of the line is

[tex]y + 2 = - \frac{4}{5} (x - 3)[/tex]

Hope this helps you

The point-slope equation of the line is given by:

[tex]y + 2 = -\frac{4}{5}(x - 3)[/tex]

What is the point-slope equation of a line?

It is given by:

[tex]y - y_0 = m(x - x_0)[/tex].

In which:

  • m is the slope.
  • [tex](x_0, y_0)[/tex] is the point.

The line that passes through (3,-2) with a slope of -4/5, hence the parameters are given by:

[tex]x_0 = 3, y_0 = -2, m = -\frac{4}{5}[/tex]

Thus, the equation of the line is:

[tex]y - y_0 = m(x - x_0)[/tex].

[tex]y - (-2) = -\frac{4}{5}(x - 3)[/tex].

[tex]y + 2 = -\frac{4}{5}(x - 3)[/tex]

More can be learned about linear functions at https://brainly.com/question/24808124

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