The area A of the rectangle shown is described with the inequality 100 ≤ A ≤ 1,000. Write and solve a compound inequality for x.

Compound inequalities is the combination of two inequalities in one inequality.
Given that:
[tex]100 \le A \le 1000[/tex]
The area (A) of the rectangle is calculated as follows:
[tex]A = Length \times Width[/tex]
So, we have:
[tex]A = 4x \times 5[/tex]
[tex]A = 20x[/tex]
Substitute 20x for A in [tex]100 \le A \le 1000[/tex]
So, we have:
[tex]100 \le 20x \le 1000[/tex]
Divide through by 20
[tex]100/20 \le x \le 1000/20[/tex]
[tex]5 \le x \le 50[/tex]
Split the above inequality
[tex]5 \le x[/tex] and [tex]x \le 50[/tex]
Rewrite as:
[tex]x \ge 5[/tex] and [tex]x \le 50[/tex]
This means that the values of x is from 5 to 50
All solutions of x are viable
Read more about compound inequalities at:
https://brainly.com/question/13290962
Answer: 5<x<50
Step-by-step explanation: area = longest side x shortest Side
Area = 4x . 5 =20x
100/20 < 20x/20< 1000/20
5<x<50