The two consecutive integers whose product is 6 less than the square of the smaller number integers are [tex]-6[/tex] and [tex]-5[/tex].
Let the two consecutive integers be [tex]x[/tex] and [tex]x+1\\[/tex] respectively.
Given, the product of both the integers is 6 less than the square of the smaller number.
So we can write it in equation form as, [tex]x\times (x+1)+6= x^{2}[/tex]
On solving ,[tex]x^{2} +x+6=x^{2}[/tex]
Further,[tex]x+6=x^{2} -x^{2}[/tex]
Or,[tex]x+6=0\\x=-6[/tex]
Now the other integer be [tex]-6+1[/tex] or [tex]-5[/tex].
Hence the two consecutive integers are [tex]-6[/tex] and [tex]-5[/tex].
For more details on consecutive numbers follow the link below:
https://brainly.com/question/864749
