Given :
Amount of cereal in smaller box , 6 + 7.1 .
Amount of cereal in big box , 12 + 6.9n ( here , n is number of small boxes ).
To Find :
The amount of cereal that the new larger boxes contains how many smaller boxes equal the same amount of cereal in the larger box.
Solution :
Let, number of boxes required to satisfy given condition is x.
So,
[tex]12 + 6.9x = (6 + 7.1)x\\\\13.1x -6.9x = 12\\\\(13.1-6.9)x=12\\\\6.2x = 12\\\\x=\dfrac{12}{6.2}\\\\x\ $\approx$ 2[/tex]
Therefore, two small boxes are required.
Hence, this is the required solution.