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Matter is in a liquid state when its temperature is between its melting point and its boiling point. Suppose that some substance has a melting point of -32.58°C

and a boiling point of 330.81°C. What is the range of temperatures in degrees Fahrenheit for which this substance is not in a liquid state? (Hint: C = (F-32))

Express the range as an inequality

Let x represent the temperature in degrees Fahrenheit. What is the range of temperatures for which this substance is not in a liquid state?

(Type an inequality or a compound inequality. Simplify your answer.

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Answer: - 26.644° < x < 627.458°

Step-by-step explanation:

Given that:

Matter = liquid ; wkens temperature is between melting and boiling point

Given a substance with:

Melting point = - 32.58°C

Boiling point = 330.81°C

range of temperatures in degrees Fahrenheit for which this substance is not in a liquid state

-32.58°C to Fahrenheit :

F = (9/5)C + 32

F = (9/5) * - 32.58° + 32°

F = - 58.644° + 32

F = - 26.644°

330.81°C

F = (9/5)C + 32

F = (9/5) * 330.81° + 32°

F = 595.458° + 32

F = 627.458°

- 26.644° < x < 627.458°

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