Answer:
Step-by-step explanation:
Let the equation of the line passing through a point (x', y') and slope 'm' is,
y - y' = m(x - x')
Since x-value increases by 3,
Δx = 3
And y-value decreases by 2,
Δy = -2
Therefore, slope = [tex]\frac{\triangle y}{\triangle x}[/tex]
Slope = [tex]-\frac{2}{3}[/tex]
Equation of the line passing through (-2, 5) and slope = [tex]-\frac{2}{3}[/tex] will be,
y - 5 = [tex]-\frac{2}{3}(x+2)[/tex]
y = [tex]-\frac{2}{3}x-\frac{4}{3}+5[/tex]
y = [tex]-\frac{2}{3}x+\frac{11}{3}[/tex]
y = [tex]\frac{1}{3}(-2x+11)[/tex]
Table for input-output values will be,
x -2 0 1 2 3
y 5 3.7 3 2.3 1.7
We can plot these points to get the line on a graph.
