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An experiment performed to determine the density of lead yields a value of 10.95 g/cm3. The accepted value for the density of lead is 11.342 g/cm3. Find the percent error.

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MikeyMoose

Answer:

3.45618%

Explanation:

Percent Error = measured value - accepted value/ accepted value x 100

Measured Value: 10.95

Accepted Value: 11.342

Work:

[tex]\frac{10.95-11.342}{11.342} *100[/tex]

[tex]\frac{-0.392}{11.342} *100[/tex] = -3.45618

You cannot have a negative percentage. Therefore the answer is 3.45618%

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