Answer:
a)value attached below
b)Yo = [tex]\frac{-27}{20}[/tex]
Step-by-step explanation:
A) solving initial value problem
[tex]y' - 5y = 15t + 3e^t[/tex]
y(0) = yo
hence the solution of the initial value problem : y(t)
Y(t) =
Attached below is the detailed solution
B) Yo = [tex]\frac{-27}{20}[/tex] separates the solutions as
t →∞
this is because when y(t) < [tex]\frac{-27}{20} y(t) tends to inifiniy[/tex]
y(t) > [tex]\frac{-27}{20} y(t) tends to inifinity[/tex]
