Which second degree polynomial function has a leading coefficient of 2 and roots –3 and 5? f(x) = 2x2 + 4x – 30 f(x) = 2x2 + 2x – 15 f(x) = 2x2 – 4x – 30 f(x) = 2x2 – 2x – 15

Respuesta :

Answer:

c

Step-by-step explanation:

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A quadratic equation is an equation whose leading coefficient is of the second degree. The correct option is C.

What is a quadratic equation?

A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers. It is written in the form of ax²+bx+c.

Its roots are given as:

[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]

The second-degree polynomial function that has roots –3 and 5 are,

f(x) = (x+3)(x-5)

f(x) = x² + 3x - 5x -15

f(x) = x² - 2x - 15

Now, it is needed that the polynomial's leading coefficient should be 2. Therefore, the polynomial should be multiplied by 2. Thus, the polynomial will be,

f(x) = 2x² - 4x - 30

Learn more about Quadratic Equations:

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