In the table H, for every value of y there is a unique value of x, therefore option H is correct.
Step-by-step explanation:
In this question we have to go through the option and find the the correct answer.
In the table F, for two or more values of y the value of x remains unchange , therefore thios option is incorrect.
In the table G, for the y values -1 and 5 the value of x is -1 (unchanged) , therefore this option is also incorrect.
In the table H, for every value of y there is a unique value of x, therefore option H is correct.
In the table J, for the y values 0 and 6 the value of x is 0 (unchanged) , therefore this option is also incorrect.
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