Respuesta :

meerkat18
The question is asking to write x^2-8x+13 in the form of (x-1)2 = b where as a and b are integers, base on the said formula, I would say that the correct answer would be (x - 4)2 = 3, I hope you are satisfied with my answer and feel free to ask for more if you have questions and further clarifications 

Answer:

A) [tex](x - 4)^2 = 3[/tex]

Step-by-step explanation:

The given equation is [tex]x^{2} -8x +13 = 0[/tex]

We have to convert this quadratic equation in the form of [tex](x -a)^{2} = b[/tex].

Here we have to use the completing square method.

Identify the value of b from the given quadratic equation.

b = -8 now divide it by 2 and square it.

[tex](\frac{b}{2})^{2}[/tex]

= [tex](\frac{-8}{2} )^2[/tex]

= [tex](-4)^{2}[/tex]

= 16

Now add 16 on both side of the equation

[tex]x^{2} - 8x + 16 + 13 = 16[/tex]

[tex](x^{2} -8x +16) +13 = 16[/tex]

Now subtract 13 on both sides, we get

[tex](x^{2} - 8x +16) + 13 -13 = 16 -13[/tex]

[tex]x^{2} -8x + 16 = 3[/tex]

Here [tex](x -4)^{2} = x^2 -8x +16[/tex]

So, we get

[tex](x - 4)^2 = 3[/tex]

Therefore, answer is A) [tex](x - 4)^2 = 3[/tex]

Otras preguntas