Answer:
x=2 and y=0 is the required result.
Step-by-step explanation:
We have been given system of equations:
[tex]5x+2y=10[/tex] (1)
And [tex]3x+2y=6[/tex] (2)
We will use elimination method:
Multiply 1st equation by 3 and 2nd equation by 5 we get:
[tex]15x+6y=30[/tex] (3)
[tex]15x+10y=30[/tex] (4)
Now subtract (4) from (3) we get:
[tex]-4y=0[/tex]
[tex]y=0[/tex]
Now, put y=0 in (1) equation:
[tex]5x+2(0)=10[/tex]
[tex]5x=10[/tex]
[tex]x=2[/tex]
Hence, x=2 and y=0
