Respuesta :
[tex]\mathrm{Domain\:of\:}\:5x+6\:[/tex]
[tex]\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:\ \textless \ x\ \textless \ \infty \\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:\infty \:\right)\end{bmatrix}[/tex]
[tex]\text{The function has no points nor domain constraints. So, the domain is}[/tex]
[tex]\mathrm{Solution:}\:&\:-\infty \:\ \textless \ x\ \textless \ \infty \\ \:[/tex]
[tex]\mathrm{Range\:of\:}5x+6[/tex]
[tex]\begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:\ \textless \ f\left(x\right)\ \textless \ \infty \\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:\infty \:\right)\end{bmatrix}[/tex]
[tex]\mathrm{The\:set\:of\:values\:of\:the\:dependent\:variable = meaning}[/tex]
[tex]\mathrm{The\:range\:of\:polynomials\:with\:odd\:degree\:is\:all\:the\:real\:numbers}[/tex]
[tex]\mathrm{Solution:}\:&\:-\infty \:\ \textless \ f\left(x\right)\ \textless \ \infty [/tex]
[tex]\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:\ \textless \ x\ \textless \ \infty \\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:\infty \:\right)\end{bmatrix}[/tex]
[tex]\text{The function has no points nor domain constraints. So, the domain is}[/tex]
[tex]\mathrm{Solution:}\:&\:-\infty \:\ \textless \ x\ \textless \ \infty \\ \:[/tex]
[tex]\mathrm{Range\:of\:}5x+6[/tex]
[tex]\begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:\ \textless \ f\left(x\right)\ \textless \ \infty \\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:\infty \:\right)\end{bmatrix}[/tex]
[tex]\mathrm{The\:set\:of\:values\:of\:the\:dependent\:variable = meaning}[/tex]
[tex]\mathrm{The\:range\:of\:polynomials\:with\:odd\:degree\:is\:all\:the\:real\:numbers}[/tex]
[tex]\mathrm{Solution:}\:&\:-\infty \:\ \textless \ f\left(x\right)\ \textless \ \infty [/tex]
