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22-09-2016
Mathematics

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given triangle abc whose sides are ab = 15 in. ac 25 in. and bc 30 in. . from a point d on side ab, a line de is drawn to a point e on side ac such that angle ade is equal to angle abc. if the perimeter of triangle ade is 28 in. in find the lengths of line segments and ce?

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22-09-2016

Hello,

Using the theorem of Thales:

[tex] \dfrac{AB+AC+BC}{AD+AE+ED} = \dfrac{AC}{AE} \\ \dfrac{70}{28} = \dfrac{25}{AE} ==\ \textgreater \ AE= \frac{25*28}{70} = 10\\ CE=CA-EA=25-10=15 [/tex]

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