Respuesta :
f(1) = 6
f(2) = 6 - 5 = 1 => f(2) = f(1) - 5
Required recursive formular => f(n + 1) = f(n) - 5
f(2) = 6 - 5 = 1 => f(2) = f(1) - 5
Required recursive formular => f(n + 1) = f(n) - 5
Which recursive formula can be used to generate the sequence below, where f(1) = 6 and n ≥ 1?
f (n + 1) = f(n) + 5
f (n + 1) = f(n) – 5 [this answer is correct]
f (n) = f(n + 1 ) – 5
f (n + 1) = –5f(n)