a broken faucet leaks one gallon of water every 1 1/3 months. the amount of months that pass, m , varies directly with the amount of gallons that are leaked, g. find the equation that models this direct variation. How many months will it take for the faucet to leak 7 gallons of water?

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RyanL

I just did this problem and the answer is B m =4/3g , 9 1/3 months

the equation that models this direct variation.

[tex]m=\frac{4}{3} g[/tex]

[tex]\frac{28}{3} \; or \; 9\frac{1}{3}[/tex]  months will it take for the faucet to leak 7 gallons of water

Given :

the amount of months that pass, m , varies directly with the amount of gallons that are leaked, g.

When y varies directly with x  then equation is [tex]y=mx[/tex]

Now we use the given information to frame equation

Month varies directly with the amount of  gallons leaked

The equation that models direct variation is

[tex]m=k(g)[/tex]

Now we find out k

a broken faucet leaks one gallon of water every 1 1/3 months

[tex]m=1\frac{1}{3}=\frac{4}{3} \\gallons g=1\\m=kg\\\frac{4}{3} =k(1)\\k=\frac{4}{3}[/tex]

Now we replace the value of 'k'

The equation that models direct variation is

[tex]m=\frac{4}{3} g[/tex]

Now we find out how many months will take for the faucet to leak 7 gallons of water

Substitute 7 for g in the above equation

[tex]m=\frac{4}{3} g\\m=\frac{4}{3} (7)\\\\m=\frac{28}{3}\\[/tex]

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