Respuesta :
ok so just do
a^2+b^2=c^2
c=longest side
a and b are the other sides
input for a and b and c and see which ones are true
A. 1^2+3^2=10^2
1+9=100
10=100
false
B, 4^2+5^2=9^2
16+25=81
41=81
false
C. 9^2+40^2=41^2
81+1600=1681
1681=1681
true
D. 16^2+30^2=44^2
256+900=1936
1156=1936
false
answer is C
a^2+b^2=c^2
c=longest side
a and b are the other sides
input for a and b and c and see which ones are true
A. 1^2+3^2=10^2
1+9=100
10=100
false
B, 4^2+5^2=9^2
16+25=81
41=81
false
C. 9^2+40^2=41^2
81+1600=1681
1681=1681
true
D. 16^2+30^2=44^2
256+900=1936
1156=1936
false
answer is C
The only Pythagorean triple is c.
Pythagorean triple
A Pythagorean triple is a set of positive integers that follows the Pythagorean theorem.
Given to us
A.1, 3, 10
B.4, 5, 9
C.9, 40, 41
D.16, 30, 44
Solution
A.) 1, 3, 10
H = 10, as 10 is the largest number in the set,
[tex]H^2 = B^2+P^2\\H^2 = 10^2 =100\\B^2+P^2=1^2+3^2 = 1+9 = 10\\100\neq 10[/tex]
As we can see that the square of the biggest number is not equal to the sum of the square of the other two numbers.
B.) 4, 5, 9
H = 9, as 9 is the largest number in the set,
[tex]H^2 = B^2+P^2\\H^2 = 9^2 =81\\B^2+P^2=4^2+5^2 = 16+25 = 41\\81\neq 41[/tex]
As we can see that the square of the biggest number is not equal to the sum of the square of the other two numbers.
C.) 9, 40, 41
H = 41, as 41 is the largest number in the set,
[tex]H^2 = B^2+P^2\\H^2 = 41^2 =1681\\B^2+P^2=9^2+40^2 = 81+1600 = 41\\1681= 1681[/tex]
As we can see that the square of the biggest number is equal to the sum of the square of the other two numbers.
D.) 16, 30, 44
H = 44, as 44 is the largest number in the set,
[tex]H^2 = B^2+P^2\\H^2 = 44^2 =1936\\B^2+P^2=16^2+30^2 = 256+900=1156\\1936\neq 1156[/tex]
As we can see that the square of the biggest number is not equal to the sum of the square of the other two numbers.
Hence, the only Pythagorean triple is c.
Learn more about Pythagorean triple:
https://brainly.com/question/16314667