Respuesta :
Answer: [tex]0.012\times 10^{23}[/tex] molecules
Explanation :
Molarity is defined as the number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n}{V_s}[/tex]
where,
n = moles of solute [tex]C_{12}H_{22}O_{11}[/tex] = ?
[tex]V_s[/tex] = volume of solution in liter = 0.0143L
Now put all the given values in the formula of molarity, we get
[tex]0.140M=\frac{n}{0.0143L}=0.002moles[/tex]
Therefore, the number of moles is 0.002.
According to Avogadro's law,
1 mole of [tex]C_{12}H_{22}O_{11}[/tex] contains [tex]6.023\times 10^{23}[/tex] molecules of sucrose.
Thus 0.002 moles of [tex]C_{12}H_{22}O_{11}[/tex] contain= [tex]\frac{6.023\times 10^{23}}{1}\times 0.002=0.012\times 10^{23}[/tex] molecules of sucrose.
[tex]\boxed{1.2044\times10^{21}\text{molecules}}[/tex] of sucrose are present in 14.3 mL of 0.140 M sucrose solution.
Further Explanation:
The concentration is the proportion of substance in the mixture. The most commonly used concentration terms are as follows:
1. Molarity (M)
2. Molality (m)
3. Mole fraction (X)
4. Parts per million (ppm)
5. Mass percent ((w/w) %)
6. Volume percent ((v/v) %)
Molarity is a concentration term that is defined as the number of moles of solute dissolved in one litre of the solution. It is denoted by M and its unit is mol/L.
The formula to calculate the molarity of sucrose is as follows:
[tex]{\text{Molarity of sucrose solution}}=\frac{{{\text{amount}}\;\left( {{\text{mol}}}\right)\;{\text{of}}\;{\text{sucrose}}}}{{\;{\text{volume }}\left( {\text{L}} \right)\;{\text{of}}\;{\text{solution}}}}[/tex]
.. (1)
Rearrange equation (1) to calculate the amount of sucrose.
[tex]{\text{Amount of}}\;{\text{sucrose}}=\left({{\text{Molarity of sucrose solution}}} \right)\left({\;{\text{Volume of sucrose }}{\text{solution}}}\right)[/tex]
…… (2)
Firstly the volume is to be converted into L. The conversion factor for this is,
[tex]{\text{1 mL}}={\text{1}}{{\text{0}}^{{\text{-3}}}}{\text{L}}[/tex]
So the volume of sucrose solution can be calculated as follows:
[tex]\begin{aligned}{\text{Volume of sucrose solution}}&=\left({{\text{14}}{\text{.3 mL}}}\right)\left({\frac{{{\text{1}}{{\text{0}}^{-3}}{\text{L}}}}{{{\text{1 mL}}}}}\right)\\&=0.0143\;{\text{L}}\\\end{aligned}[/tex]
The molarity of the sucrose solution is 0.140 M.
The volume of sucrose solution is 0.0143 L.
Substitute these values in equation (2)
[tex]\begin{aligned}{\text{Amount}}\;{\text{of}}\;{\text{sucrose}}&=\left({{\text{0}}{\text{.140 M}}}\right)\left({0.0143\;{\text{L}}} \right)\\&=0.002002\;{\text{mol}}\\&\approx{\text{0}}{\text{.002 mol}}\\\end{aligned}[/tex]
According to Avogadro law, one mole of any substance contains [tex]{\mathbf{6}}{\mathbf{.022\times1}}{{\mathbf{0}}^{{\mathbf{23}}}}[/tex] molecules.
So the number of molecules of sucrose is calculated as follows:
[tex]\begin{aligned}{\text{Number of molecules in sucrose}}{\mathbf{&=}}\left({0.002\;{\text{mol}}}\right)\left({\frac{{{\text{6}}{\text{.022}}\times{\text{1}}{{\text{0}}^{{\text{23}}}}{\text{ molecules}}}}{{{\text{1 mol}}}}}\right)\\&={\mathbf{1}}{\mathbf{.2044 \times 1}}{{\mathbf{0}}^{{\mathbf{21}}}}\;{\mathbf{molecules}}\\\end{aligned}[/tex]
Learn more:
1. What is the mass of 1 mole of viruses: https://brainly.com/question/8353774
2. Determine the moles of water produced: https://brainly.com/question/1405182
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Concentration terms
Keywords: molarity, sucrose, moles, molecules, Avogadro’s law, molarity of sucrose solution, volume, 0.140 M, 0.002 mol, concentration, proportion, substance, molality, parts per million, mass percent, volume percent, mole fraction, concentration terms, m, M, X, (w/w) %, (v/v) %, conversion factor.
