Respuesta :

clache
t^2-t=12
t^2-t-12=0
(t-4)(t+3)=0

t=4, -3

Answer:

The given quadratic equation [tex]t^2-t=12[/tex] can be factorized as [tex](t+3)(t-4)[/tex] using middle term splitting method.

Step-by-step explanation:

Consider the given quadratic equation [tex]t^2-t=12[/tex]

It can be written as [tex]t^2-t-12=0[/tex]

We can factorize it using middle term splitting method,

[tex]t^2-t-12=0[/tex]

-t can be written as (-4t+3t ) such that their product is -12 then,

[tex]\Rightarrow t^2-4t+3t-12=0[/tex]

[tex]\Rightarrow t(t-4)+3(t-4)=0[/tex]

[tex]\Rightarrow (t+3)(t-4)=0[/tex]

Thus, the given quadratic equation [tex]t^2-t=12[/tex] can be factorized as [tex](t+3)(t-4)[/tex] using middle term splitting method.