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Find two consecutive even integers such that four times the first plus three times the second is 20

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texaschic101
2 consecutive even integers : x and x + 2

4(x) + 3(x + 2) = 20
4x + 3x + 6 = 20
7x + 6 = 20
7x = 20 - 6
7x = 14
x = 14/7
x = 2

x + 2 = 2 + 2 = 4

so ur first number (x) = 2 and ur second number (x + 2) = 4