An airport has runways only 145 m long. A small plane must reach a ground speed of 44 m/s before it can become airborne. What average acceleration must the plane’s engines provide if it is to take off safely from its airport?

Respuesta :

Answer:

The value  is  [tex]a = 6.676 \ m/s^2[/tex]  

Explanation:

From the question we are told that  

  The length of the runways is  [tex]l =145 \ m[/tex]

  The required ground of a small plane is  [tex]v = 44 \ m/s[/tex]

Generally from kinematics equation

       [tex]v^2 = u^2 + 2as[/tex]

Here u  is the initial speed of the plane which is 0 m/s

so

      [tex]44^2 = 0^2 + 2 * a* 145[/tex]

=>  [tex]a = 6.676 \ m/s^2[/tex]