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Suppose that a rectangular picture is surrounded by a frame of uniform width of x
inches as depicted below. The dimensions of the picture are 8 inches (width) by
10 inches (length). Find a simplified expression that represents the area of the
picture and frame.
Type your simplified answer for the area of the picture and frame along with your
work in the box below. To receive any partial credit, you must include all your work.

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Answer:

Ok so the area of the frame is 18*12 = 216cm^2

Let’s suppose the width of the frame is x

The total area (painting and frame) is (2x+18)(2x+12) and this is equal to 432

4x^2 + 60x + 216 = 432

4x^2 + 60x - 216 = 0

x^2 + 15x - 54 = 0

(x+18)(x-3) = 0

Therefore x = {-18,3}

Since width of the frame has to be positive, the width has to be 3cm Step-

i hope i helped!

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