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Sound intensity, in decibels, d, can be written using a comparison factor, x, that compares sound intensity to the standard threshold of hearing. d = 10log(x) A sensor measures the sound intensity, in decibels, of an office over time. The decibel reading was consistently above 50, but never above 70. On what interval is the factor by which the office noise is related to the standard threshold of hearing? (17, 18.5) (17, 18.5] (100,000, 10,000,000] (100,000, 10,000,000)

Respuesta :

Answer: (100,000, 10,000,000]

Step-by-step explanation:

The interval is given by ( 100,000 , 10,000,000], the correct option is C.

What is the Threshold Value ?

The threshold value is the minimum value above which the desired results can be expected.

The decibel reading was consistently above 50, but never above 70.

d = 10log(x)

50 = 10log(x)

5 = log x

10⁵ = x

x > 10⁵

d = 10log(x)

70 = 10log(x)

x = 10⁷

From the given data

x ≤ 10⁷

Therefore, the interval is given by ( 100,000 , 10,000,000], the correct option is C.

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