A hypothetical metal has the simple cubic (SC) crystal structure. If its atomic weight is 70.4 g/mol and the atomic radius is 0.126 nm. Compute its density (in g/cm3)

Respuesta :

Answer:

[tex]7304g/cm^3[/tex]

Explanation:

Density is the mass per unit volume, it is usually measured in kg/m³.

The density of a crystal structure is given by:

[tex]\rho=\frac{mass\ of\ atoms\ in\ unit\ cell}{volume\ unit\ cell} =\frac{nA}{V_cN_A} \\\\\rho=density, n= number\ of\ atoms/unit=1\ atom/unit\ cell,A=atomic\ weight=70.4\ g/mol,N_A=avogadro\ constant=6.023*10^{23}atoms/mol,V=volume=2R^3=[2(0.126*10^{-8})]^3cm\\\\\rho=\frac{1*70.4}{[2(0.126*10^{-8})]^3*6.023*10^{23}} =7304g/cm^3[/tex]

Answer:

7.307g/cm^3

Explanation:

The other guy is mostly right but his conversion factor was off. It should be 1.26x10^-8 on the bottom