The price of Stock A at 9 A.M. was $13.11. Since then, the price has been increasing at the rate of $0.06 each hour. At noon the price of Stock B was $13.86. It begins to decrease at the rate of $0.15 each hour. If the two rates continue, in how many hours will the prices of the two stocks be the same?
In about nothing hours,

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jelynch jelynch · Answer 1 · 2020-10-22T11:56:23+02:00

Answer:

2 hrs 43 minutes or 2.7143 hours

Step-by-step explanation:

At 9am the stock is at $13.11. By noon (3 hours time) the share price is $13.29 as $13.11 + 3*(0.06) = $13.29

So at noon, Stock A is at $13.29 and will increase at $6c per hour

Stock B is at $13.86 and will decrease at $15c per hour

Let's use "x" to solve for hours and set these equations equal to each other

$13.29 + x(0.06) = $13.86 - x(0.15)

Solve for x

0.06x + 0.15x = 13.86 - 13.29

0.21x = 0.57

divide both sides by 0.21

x = 0.57/0.21

x = 2.7143 hours

0.7143 hours is 0.7143 * 60 minutes

= 42.8 minutes

so final answer is 2 hours and 43 minutes... I think!