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a certain journey took 40 min to complete. if half of the distance was travelled at an average speed of 100 km/h and the other half at an average speed of 60 km/h, what was the total length​ of the journey

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total time taken = 40 min

let x be the total length/ distance of the journey.

speed(v) = distance/ time

100= (1/2 x)/ time ---1

60= (1/2 x)/ time ---2

add 1 and 2

160= x/40

where 40 is the total time taken

44.44m/s= x/ 2400s (i converted the speed and time)

x = 106,656 metres = 106.656km

the total length is 106.656 km.

Answer:

50 kilometers

Step-by-step explanation:

a + b = (40/60)

a + b = 2/3

a = (2/3) - b

100 * ((2/3) - b) = d/2

60 * b = d/2

100 * ((2/3) - b) = 60 * b

(200/3) - 100b = 60b

200/3 = 160b

20/3 = 16b

5/3 = 4b

5/12 = b

(2/3 - 5/12) = a

(3/12) = a

1/4 = a

100 * (1/4) + 60 * (5/12) =>

25 + 25 =>

50

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