Answer:
The answer is "[tex]\bold{ \mu =0.967, x=3, \ and \ e= 2.718}[/tex]".
Step-by-step explanation:
A distribution of poulet applies because it deals through events (bomb hits) over even a sample space (the region with [tex]0.95 \ km^2[/tex] area).
Its average hit number per area is:
[tex]\to \mu = \frac{\text{Number of hits of bomb}}{ \text{number of regions number}}[/tex]
[tex]=\frac{535}{553} \\\\= 0.967 \\\\[/tex]
[tex]\to x = 3\\\\\to e = 2.718[/tex]
