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Do 2. A cyclist starts from rest and accelerates along a straight path to a speed of
12.15 m/s in a time of 4.5 seconds.
What is the cyclist's acceleration to the nearest tenth?
O
54.7 m/s2
o
24.3 m/s?
2.7 m/s2
De
3.4 m/s?

Respuesta :

Lanuel

The cyclist's acceleration to the nearest tenth is: C. 2.7 [tex]m/s^2[/tex].

Given the following data:

  • Initial velocity = 0 m/s (since the cyclist starts from rest).
  • Final velocity = 12.5 m/s.
  • Time = 4.5 seconds.

To find the cyclist's acceleration to the nearest tenth:

Acceleration is calculated by subtracting the initial velocity from the final velocity and dividing by the time.

Mathematically, acceleration is given by the formula;

[tex]A = \frac{V - U}{t}[/tex]

Where:

  • A is the acceleration.
  • V is the final velocity.
  • U is the initial velocity.
  • t is the time measured in seconds.

Substituting the given parameters into the formula, we have;

[tex]A = \frac{12.5\; - \;0}{4.5} \\\\A = \frac{12.5}{4.5}[/tex]

Acceleration, A = 2.7  [tex]m/s^2[/tex]

Therefore, the cyclist's acceleration to the nearest tenth is 2.7 [tex]m/s^2[/tex].

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