Answer:
0.01228 moles OH⁻
Explanation:
The reaction of H₂SO₄ with KOH is:
H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O
Thus, we need to determine the moles of H2SO4 and KOH that reacts:
Moles H₂SO₄:
0.02173L * (0.142mol/L) = 3.086x10⁻³mol
Moles KOH:
0.04893L * (0.377mol/L) = 0.01845 mol KOH
The moles of KOH that reacts are:
3.086x10⁻³mol H₂SO₄ * (2 mol KOH / 1 mol H₂SO₄) = 6.172x10⁻³ moles KOH
And will remain in solution:
0.01845 mol KOH - 6.172x10⁻³ moles KOH = 0.01228 moles of KOH =
0.01228 moles OH⁻
