What is the heat of a reaction, in joules, with a total reaction mixture volume of 62.3 mL of the reaction causes a temperature change of 5.0 oC in a calorimeter

The first thing to do is to calculate or Determine the mass. Thus, from the question/problem above some basic parameters or data or information were provided which is going to aid in solving this particular Question;

=> total reaction mixture volume =62.3 mL and the reaction temperature change = of 5.0 oC

The mass = density × total reaction mixture volume = 1 × 62.3 = 62.3 grams.

Therefore, the heat of a reaction = mass × specific heat capacity (C) × temperature change (∆T).

Thus, the heat of reaction = 62.3 grams × 4.184 J/g-°C × 5.0°C = 1,303.316 J = 1.303316 KJ.

pstnonsonjoku pstnonsonjoku · Answer 2 · 2021-10-22T16:48:05+02:00

The heat of reaction is 1.3 KJ.

From the information available in the question;

Volume of water = 62.3 mL

Since the density of water is 1 g/mL

Density = mass/volume

Mass of water = Density × volume

Mass of water = 1 g/mL × 62.3 mL

Mass of water = 62.3 g or 0.0623 Kg

Temperature change = 5.0 oC

Specific heat capacity of water= 4200 J/Kg

From;

H = mcθ

m = mass of water

c = heat capacity of water

θ = temperature rise

Substituting values;

H = 0.0623 Kg × 4200 J/Kg × 5.0 oC

H = 1.3 KJ

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