We want to graph a line with a slope of -5 that contains the point (-3, -4), the graph can be seen at the end.
Getting the equation:
We first need to get the equation of the line that we must graph.
The general line equation is:
y = a*x + b
Where a is the slope and b is the y-intercept.
Here we know that the slope must be -5, so we have:
y = -5*x + b
And we know that it must contain the point (-3, -4), then we can replace these values for x and y in the equation and solve it for b:
-4 = -5*-3 + b
-4 = 15 + b
-4 - 15 = b
-19 = b
Then the linear equation is:
y = -5*x - 19
To graph this you just need to find two points on the line and then connect them with a line, we already know one (-3, -4). To get another we can evaluate the equation in any value of x, for example with x = 0 we get:
y = -5*0 - 19
y = -19
Then the other point is (0, -19)
With these two points you will get the graph below:
If you want to learn more about linear equations, you can read:
https://brainly.com/question/4074386
